Key ideas
Aldehydes and ketones share the carbonyl group C=O, whose carbon is attacked by nucleophiles. Aldehydes have a hydrogen on the carbonyl carbon, which makes them easy to oxidize.
- Tollens’ test (silver mirror) and Fehling’s test are positive for aldehydes and negative for ketones, because only aldehydes are easily oxidized.
- The iodoform test is positive for methyl ketones R–CO–CH₃ and for CH₃CH(OH)–R, as well as for ethanal.
- Nucleophilic addition: HCN gives a cyanohydrin, and a Grignard reagent adds R′ to give an alcohol, secondary from an aldehyde and tertiary from a ketone.
- Reduction with NaBH₄ or LiAlH₄ gives a primary alcohol from an aldehyde and a secondary alcohol from a ketone. Aldol reactions need an α-hydrogen.
Key equations
RCHO + [Ag(NH₃)₂]⁺ → RCOO⁻ + AgR₂C=O + HCN → R₂C(OH)CNRCHO + R′MgX → 2° alcoholR₂C=O + R′MgX → 3° alcohol
Worked example
Propanone + CH₃MgBr, then H₃O⁺, gives 2-methylpropan-2-ol, a tertiary alcohol. To tell ethanal from propanone, Tollens’ reagent gives a silver mirror with ethanal only. To tell propanone from propanal, the iodoform test is positive for propanone only.
Common mistakes
- Expecting a ketone to give a silver mirror with Tollens’ reagent.
- Giving a primary alcohol as the product of a Grignard reaction with a ketone. A ketone gives a tertiary alcohol.
- Forgetting that an aldol reaction needs a hydrogen on the carbon next to the carbonyl.
Practice
Test yourself with practice questions on this topic: Aldehydes and ketones