Molar Mass of CuSO4·5H2O

How to work out the molar mass of CuSO4·5H2O

1. Count the atoms of each element in CuSO4·5H2O: 1 Cu, 1 S, 9 O and 10 H.
2. Multiply each count by the element's atomic weight: 1 × 63.546 = 63.546; 1 × 32.06 = 32.060; 9 × 15.999 = 143.991; 10 × 1.008 = 10.080.
3. Add the results: 63.546 + 32.060 + 143.991 + 10.080 = 249.677 g/mol.

Frequently asked questions

What is the molar mass of CuSO4·5H2O?

The molar mass of copper(II) sulfate pentahydrate (CuSO4·5H2O) is 249.677 g/mol, so one mole of it weighs 249.677 grams.

How many moles are in 100 grams of CuSO4·5H2O?

100 g ÷ 249.677 g/mol = 0.401 mol.

Which element makes up most of the mass of CuSO4·5H2O?

O, at 57.67% of the mass.